From Newsgroup: comp.lang.python.announce

Hi all,

happy to announce a better developer experience with pytest-when fixture.

With pytest-mock you can define the complex mocking behavior via natural interface:

```
when(some_object, "attribute").called_with(1, 2).then_return("mocked")
```

In this case the some_object.attribute(1, 2) == "mocked". But if it will be called with any other
arguments, it will return what it is suppose to return.


Project GitHub:
https://github.com/zhukovgreen/pytest-when
zhukovgreen/pytest-when: Pytest plugin for more readable mocking
github.com

Support python>=3.8 and tested until 3.11


Small example from the docs:
# class which we're going to mock in the test
class Klass1:
def some_method(
self,
arg1: str,
arg2: int,
*,
kwarg1: str,
kwarg2: str,
) -> str:
return "Not mocked"


def test_should_properly_patch_calls(when):
when(Klass1, "some_method").called_with(
"a",
when.markers.any,
kwarg1="b",
kwarg2=when.markers.any,
).then_return("Mocked")

assert (
Klass1().some_method(
"a",
1,
kwarg1="b",
kwarg2="c",
)
== "Mocked"
)
assert (
Klass1().some_method(
"not mocked param",
1,
kwarg1="b",
kwarg2="c",
)
== "Not mocked"
)

# if you need to patch a function
def test_patch_a_function(when):
when(example_module, "some_normal_function").called_with(
"a",
when.markers.any,
kwarg1="b",
kwarg2=when.markers.any,
).then_return("Mocked")

assert (
example_module.some_normal_function(
"a",
1,
kwarg1="b",
kwarg2="c",
)
== "Mocked"
)
assert (
example_module.some_normal_function(
"not mocked param",
1,
kwarg1="b",
kwarg2="c",
)
== "Not mocked"
)


Thank you for any feedback

--
zhukovgreen,

Data Engineer @Paylocity
https://github.com/zhukovgreen

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